- #1
Vriska
- 138
- 2
Homework Statement
I have 2 thin rods of length L in the axial plane(x axis), they're of the same uniform linear charge distribution and are separated by a distance a .
Homework Equations
$$E = \frac{kq} {R^2}$$
$$F = qE$$
The Attempt at a Solution
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Let 0 be one at one end of the two rod systems such that the first rod terminate at L and the other rod begins at L+ a.
Then field E due to first rod at some point a =
$$\int \frac{\lambda k dx}{(L + a - x)^2} $$ evaluated from x = 0 to x = L. This is $$\frac{L}{a(L+a)}$$. Now I find the force on the second charge $$ dF = E'(x) dq$$ we note here that E'(x) = E(a +x) integrating this from 0 to L. gives you the wrong answer : (
Ps. Where can I find more of these infinitismal problems for practice?