Force of one dipole on another; non-symmetric

In summary, a dipole is a physical object or system with two opposite charges separated by a small distance, creating a dipole moment. The force between two dipoles depends on their distance, charge strength, and relative orientation. It can be either attractive or repulsive, and asymmetry in charge distribution can result in a non-symmetric force. Dipoles have many real-world applications in fields such as magnetism, electricity, and technology design.
  • #1
mhryciw
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Homework Statement


The dipole p1 lies on the z axis at the origin. p2 is at a distance r away . Using cylindrical coordinates, p2 is at angle θ down from the z axis (see diagram), and points in the z direction. r is assumed to be much greater than d (distance between charged ends of dipole) therefore are evaluated as pure dipoles. I need to find the force of p1 on p2.
The question encourages us to refer back to the derivation of the formula: F=(p[itex]\cdot[/itex][itex]\nabla[/itex])E

Homework Equations


V=(p1cosθ)/(4∏ε0r2)
E(r,θ)=-[itex]\nabla[/itex]V(r,θ)

The Attempt at a Solution


There is no dependence on ∅.
The E-field by the potential is:
E(r,θ)=|p|/(4∏ε0r3)(2cosθ[itex]\hat{r}[/itex]+sinθ[itex]\hat{θ}[/itex])
I'm just unsure of how to solve this. Do I multiply the |p|/(4∏ε0r3) component into the (2cosθ[itex]\hat{r}[/itex]+sinθ[itex]\hat{θ}[/itex]) and then take the gradient of that beast? Just point me in the right direction please! :)
 

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  • #2


it is important to approach problems in a systematic and logical manner. In this case, we are given the position and orientation of two dipoles and are asked to find the force between them. The first step would be to determine the electric potential at the location of p2 due to p1. This can be done using the given formula for the potential:

V=(p1cosθ)/(4∏ε0r2)

Next, we can use the definition of electric field to find the electric field at the location of p2:

E(r,θ)=-\nablaV(r,θ)

Since we are using cylindrical coordinates, we can express the electric field in terms of the unit vectors in the cylindrical basis:

E(r,θ)=E_r(r,θ)\hat{r}+E_θ(r,θ)\hat{θ}+E_z(r,θ)\hat{z}

Where E_r, E_θ, and E_z are the components of the electric field in the r, θ, and z directions respectively. We can use this expression to find the force on p2 due to p1 using the formula:

F=(p\cdot\nabla)E

Where p is the dipole moment of p2. This formula takes into account the orientation of the dipole and gives us the force in the direction of the dipole moment.

In summary, to find the force of p1 on p2, we need to first find the electric potential at the location of p2 due to p1, then use the definition of electric field to find the components of the electric field, and finally use the formula for force to find the force in the direction of the dipole moment. I hope this helps guide you in the right direction.
 

FAQ: Force of one dipole on another; non-symmetric

What is a dipole?

A dipole is a physical object or system that has two equal and opposite charges separated by a small distance. This creates a dipole moment, which is a measure of the strength and direction of the dipole.

How does one dipole exert a force on another dipole?

The force between two dipoles is dependent on the distance between them and the strength of each dipole's charge. It is also influenced by the orientation of the dipoles relative to each other. Dipoles that are aligned in the same direction will experience a stronger force compared to dipoles that are misaligned.

Is the force between two dipoles always attractive?

No, the force between two dipoles can be either attractive or repulsive depending on their relative orientations. If the dipoles are aligned in opposite directions, the force will be attractive. If the dipoles are aligned in the same direction, the force will be repulsive.

How does asymmetry affect the force between two dipoles?

Asymmetry in the distribution of charge within a dipole can result in a non-symmetric force between two dipoles. This means that the force experienced by each dipole will be different, and the overall force on the system will not be symmetrical.

What are some real-world applications of dipoles and their forces on each other?

Dipoles play a crucial role in many physical phenomena, such as magnetism, electricity, and chemical bonding. They are also used in various technologies, including capacitors, antennas, and MRI machines. Understanding the force between dipoles is essential in designing and optimizing these technologies.

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