Force of one wire due to the other

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In summary, using the given values of D=1.0cm=0.01m and I=1.0A, the magnetic field B produced by a wire carrying 1 amp at a distance of 10 cm is 2.0x10^-5. To find the magnitude of the force on the wire in this field, the equation F=ILBsinθ can be used, where L is the length of the wire and B is the magnetic field. The unit of force is N/m. This is a two step process, first determining the B field and then using that to determine the force on the wire.
  • #1
aChordate
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Homework Statement



3.jpg


D=1.0cm=0.01m
I=1.0A


Homework Equations


B=(μ0I)/(2∏r)

The Attempt at a Solution



B1=(4∏x10^-7 * 1.0A)/(2∏ * 0.01m)= 2.0x10^-5

B2=(4∏x10^-7 * 1.0A)/(2∏ * 0.01m)= 2.0x10^-5

Not sure what to do with these two numbers.
 
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  • #2
How does the force on a wire relate to the current through the wire and the B field?
 
  • #3
I would use the Right Hand Rule to find the relation. Since the current is going upward (thumb), the magnetic field B would be going into the page (fingers) and the force would be pointing to the left (direction the palm faces).
 
  • #4
The right hand rule will give the direction of the force but not the magnitude. You have found B, the magnetic field produced by a wire carying 1 amp at a distance of 10 cm. Now How do you find the magnitude of the force on the wire that is in this field?
 
  • #5
Would I use F=|q0|vBsinθ ?
 
  • #6
Wait, nevermind. That would be for a moving particle.
 
  • #7
F = BIL, remember this?
 
  • #8
F=ILBsinθ would be the equation, I think.
 
  • #9
Oh, saw your post after I posted. Oops. What would be L? I thought that L was the length of the wire, but that was not a given variable.
 
  • #10
If you have studied Vectors i would suggest you use the more general equation force that is i*L(cross)B
 
  • #11
F=ILBsinθ is technically correct and is used if the wire is not perpendicular to the B field which it is in this case. s far as what is L, look it up in your text. It will do you some good :-) Remember the force requested is per unit length.
 
  • #12
Oh ok, so...

F/L=(1.0A)(2x10^-5)

and sin90=1

So F/L=2*10^-5
 
  • #13
would the units be Gauss/meter?
 
  • #14
What is the unit of force?
 
  • #15
oops, N/m!
 
  • #16
Remember that this is a two step process. Step 1 is to determine the B
field in the vicinity of the wire, and step 2 is to determine the force on the wire due to the B field generated by the other wire..
 

FAQ: Force of one wire due to the other

What is the force of one wire on another?

The force between two wires is caused by the interaction of their electric currents. The force is attractive if the currents are flowing in the same direction, and repulsive if the currents are flowing in opposite directions.

How do you calculate the force between two wires?

The force between two wires can be calculated using the formula F = (μ0 x I1 x I2 x L) / (2π x d), where μ0 is the magnetic constant, I1 and I2 are the currents in the wires, L is the length of the wires, and d is the distance between them.

What factors affect the force between two wires?

The force between two wires is affected by the magnitude of the electric currents in the wires, the distance between the wires, and the length of the wires. The force is also affected by the magnetic properties of the wires and the medium in which they are placed.

Can the force between two wires be repulsive?

Yes, the force between two wires can be repulsive if the currents in the wires are flowing in opposite directions. This is because the magnetic fields created by the currents will be in opposite directions, causing repulsion between the wires.

How does the force between two wires relate to the strength of the magnetic field?

The force between two wires is directly proportional to the strength of the magnetic field created by the electric currents in the wires. This means that as the magnetic field becomes stronger, the force between the wires will also increase.

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