- #1
Elementard
- 4
- 1
- Homework Statement
- A light spring having a force constant of 145 N/m is used to pull a 6.00 kg sled on a horizontal frictionless ice rink. The sled has an acceleration of 1.80 m/s2.
By how much does the spring stretch if it pulls on the sled horizontally?
- Relevant Equations
- Fs= -kx
Fp= ma
m=6.00Kg
K=145N/m
a=1.80m/s
Fp=Fs
ma=-kx
(6)(1.8)=-(145)x
x=-0.0745m
I’m just wondering why I see some people make Fs=kx instead of -kx? isn’t the force of a spring a vector?
K=145N/m
a=1.80m/s
Fp=Fs
ma=-kx
(6)(1.8)=-(145)x
x=-0.0745m
I’m just wondering why I see some people make Fs=kx instead of -kx? isn’t the force of a spring a vector?