Force on projected object at its highest point. What is the net force?

In summary, at its highest point, a ball with a weight of 1.0 N thrown at an angle of 30 degrees above the horizontal with an initial speed of 12 m/s and no air resistance has a net force of 1 N acting on it due to gravity. The correct answer is E. None of the above.
  • #1
peterpam89
5
0

Homework Statement


A ball with a weight of 1.0 N is thrown at an angle of 30 degrees above the horizontal with an initial speed of 12 m/s. There is no air resistance acting on the ball. At its highest point, the net force on the ball is:
A. 4.9 N, 30 degrees below horizontal
B. zero
C. 4.9 N up
D. 4.9 N down
E. None of the above

Homework Equations


Fnet= ma

The Attempt at a Solution



I am guessing that since there is no wind resistance, there is no acceleration in the X direction. Thus, the horizontal force is zero.

The force in the y direction should remain constant because gravity is a constant (9.8 m/s^2) and the mass is a constant. Thus, I am thinking that the net force should equal 1N.
My answer would be E. None of the above. I always get paranoid about choosing none of the above as my answer. Could someone please confirm that this is the proper way of going about this question?

Thank you so much!
-peterpam89
 
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  • #2
peterpam89 said:

Homework Statement


A ball with a weight of 1.0 N is thrown at an angle of 30 degrees above the horizontal with an initial speed of 12 m/s. There is no air resistance acting on the ball. At its highest point, the net force on the ball is:
A. 4.9 N, 30 degrees below horizontal
B. zero
C. 4.9 N up
D. 4.9 N down
E. None of the above


Homework Equations


Fnet= ma


The Attempt at a Solution



I am guessing that since there is no wind resistance, there is no acceleration in the X direction. Thus, the horizontal force is zero.

The force in the y direction should remain constant because gravity is a constant (9.8 m/s^2) and the mass is a constant. Thus, I am thinking that the net force should equal 1N.
My answer would be E. None of the above. I always get paranoid about choosing none of the above as my answer. Could someone please confirm that this is the proper way of going about this question?

Thank you so much!
-peterpam89

I would say your reasoning is spot on.

I hope I did not break any forum rules,
if so, I apologize.
 
  • #3
Yup, it's 1 N. Gravity is the only force that can possibly act on the mass: there's no air resistance, friction, electromagnetism, nuclear forces, or divine intervention to consider, so the net force is due only to gravity and gravity exerts 1 N.
 
  • #4
Great- thanks! :smile:
 

FAQ: Force on projected object at its highest point. What is the net force?

1. What is the force acting on a projected object at its highest point?

The force acting on a projected object at its highest point is known as the net force, which is the combination of all forces acting on the object.

2. How is the net force calculated at the highest point of a projected object?

The net force at the highest point of a projected object can be calculated by adding together all the individual forces acting on the object, taking into account their direction and magnitude.

3. Is the net force at the highest point of a projected object always zero?

No, the net force at the highest point of a projected object is not always zero. It depends on the individual forces acting on the object. If the forces are balanced, the net force will be zero, but if they are unbalanced, there will be a nonzero net force.

4. What factors affect the net force at the highest point of a projected object?

The net force at the highest point of a projected object can be affected by factors such as the mass and velocity of the object, as well as any external forces acting on it.

5. Why is it important to consider the net force at the highest point of a projected object?

Considering the net force at the highest point of a projected object is important because it determines the object's motion and acceleration. It also helps to understand the forces involved in the object's trajectory and can be used to predict its future motion.

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