Force on rectangular loop by a current in a long straight wire

In summary, the force experienced by a rectangular loop due to a current in a long straight wire is a result of the magnetic field generated by the wire. The magnetic field creates a force on the segments of the loop that are perpendicular to the wire, leading to a net force on the loop. The direction of this force can be determined using the right-hand rule, and its magnitude depends on the current in the wire, the length of the loop, and the distance between the loop and the wire. This interaction illustrates the principles of electromagnetism and the forces between current-carrying conductors.
  • #1
cherry
20
6
Homework Statement
Consider a long straight wire near a rectangular loop of wire as shown below. The bottom of the rectangle is a distance d = 5.0 cm from the straight wire at its nearest approach, with length L = 16.0 cm and width r = 9.0 cm (so the far edge is at distance d+r from the straight wire).

When I1 = 100.0A and I2 = 40.0A, each in the direction indicated with the arrows, what is the net force on the rectangle of wire?
Relevant Equations
B = μI/2πd
F = Il x B
Hi, I am struggling to get the right answer for this question.
Screenshot 2024-03-17 at 3.41.55 PM.png

My first thought was that I should consider to what direction does each segment of wire have a force towards.
I found the direction to be in the following (see red arrows):
Screenshot 2024-03-17 at 3.42.20 PM.png



My past attempt was:
Floop = IlooplloopBwire
Since Bwire = μo Iwire / 2πd
= 2 * 10-7 * 40 * 0.16 * 100 / 0.05
= 2.56 x 10-3

What I am confused is first of all, is that the force on the rectangular loop is DOWN and not UP (I got this from a multiple choice question that asked for the direction of the force on the rectangular loop).

Am I missing something in this question?
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?

Thank you!
 
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  • #2
Hi,
You have me wondering what you are calculating, why and especially: how ?

The exercise asks for the force on the loop. So you need B wire, but is that a single value ?

Also, I wonder about the red arrows...
 
  • #3
BvU said:
Hi,
You have me wondering what you are calculating, why and especially: how ?

The exercise asks for the force on the loop. So you need B wire, but is that a single value ?

Also, I wonder about the red arrows...
My understanding of the question was that since current is a single value, the magnetic field is uniform across the wire and the rectangular loop. Hence, why B wire is also a single value.

I got the direction of force using the RHR.
 
  • #4
cherry said:
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?
Yes, but you need to get the directions of the forces correctly. Note that segments on opposite sides of the loop carry antiparallel currents. Do antiparallel currents attract or repel?
 
  • #5
cherry said:
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?
Yes, because this is wrong:
cherry said:
My understanding of the question was that since current is a single value, the magnetic field is uniform across the wire and the rectangular loop. Hence, why B wire is also a single value.
To find the field from the wire at the loop you divided by d, but that only gives the field at the nearest part of the loop. It will be less elsewhere.
 

FAQ: Force on rectangular loop by a current in a long straight wire

What is the force on a rectangular loop placed near a long straight current-carrying wire?

The force on a rectangular loop near a long straight current-carrying wire is due to the magnetic field generated by the wire. This magnetic field interacts with the current in the loop, resulting in a force that can be calculated using the Biot-Savart law and Lorentz force principles.

How do you calculate the magnetic field generated by a long straight current-carrying wire?

The magnetic field (B) at a distance (r) from a long straight wire carrying a current (I) can be calculated using Ampère's Law: \( B = \frac{\mu_0 I}{2 \pi r} \), where \( \mu_0 \) is the permeability of free space.

How does the orientation of the rectangular loop affect the force experienced by it?

The orientation of the rectangular loop relative to the long straight wire determines the direction and magnitude of the force. If the loop is parallel to the wire, the forces on opposite sides of the loop can cancel out or add up, depending on the direction of the current in the loop and the wire.

What role does the distance between the wire and the loop play in the force calculation?

The distance between the wire and the loop is crucial in determining the magnetic field strength at the location of the loop. The force experienced by the loop is inversely proportional to the distance from the wire, as the magnetic field decreases with increasing distance from the wire.

Can the force on the rectangular loop be attractive or repulsive?

Yes, the force on the rectangular loop can be either attractive or repulsive depending on the direction of the currents in the wire and the loop. If the currents are in the same direction, the force is attractive; if they are in opposite directions, the force is repulsive.

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