- #1
pawansrao
- 1
- 0
Am designing a three wheeled cycle. The total gross weight of my vehicle including the frame + riders will be around 300Kg, which has to move at 20Kmph(5.55 m/s) speed . The basic driving force will be provided by pedaling.
Assuming the least acceleration to start from rest as 0.2m/s^2, how should i calculate the pedal force required?
I started with this approach -
Step 1: Acceleration = 0.2m/s^2
Step 2: Total force required = Rolling Frictional force + Accelerating Force
= 0.005*300*9.81 + 300*0.2 = 74.7 N
Step 3: Wheel Torque = Force X Wheel radius = 74.7*0.3 = 22Nm.
Step 4: Assuming no Gearing between wheel and pedal, Pedal Torque = Pedal force*Radius of pedal
So i get pedal force = 22 / (0.18) = 122 N
I my method/approach correct ?
Here I have used just the linear velocity and acceleration, since am dealing with pedals and wheels should I deal with the rotational velocity and acceleration?
Assuming the least acceleration to start from rest as 0.2m/s^2, how should i calculate the pedal force required?
I started with this approach -
Step 1: Acceleration = 0.2m/s^2
Step 2: Total force required = Rolling Frictional force + Accelerating Force
= 0.005*300*9.81 + 300*0.2 = 74.7 N
Step 3: Wheel Torque = Force X Wheel radius = 74.7*0.3 = 22Nm.
Step 4: Assuming no Gearing between wheel and pedal, Pedal Torque = Pedal force*Radius of pedal
So i get pedal force = 22 / (0.18) = 122 N
I my method/approach correct ?
Here I have used just the linear velocity and acceleration, since am dealing with pedals and wheels should I deal with the rotational velocity and acceleration?