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dwagz
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Homework Statement
Three forces are applied to an object, as shown in the figure. Force F1 has a magnitude of 26.8 Newtons (N) and is directed 30.0° to the left of the +y axis. Force F2 has a magnitude of 15.2 N and points along the +x axis. A third force F3 is applied such that the vector sum of the three forces is 0 N. What are (a) the magnitude and (b) direction of this third force? Specify the direction as a positive angle relative to the negative x axis, as shown in the figure.
Picture: http://s236.photobucket.com/albums/ff132/airpenny123/?action=view¤t=ch01p_46.gif
Homework Equations
F3X = F1X + F2X
F3Y = F1Y + F2Y
F3= √F3X^2 + F3Y^2
The Attempt at a Solution
F1X = (-26.8N)(.8660)
F1X = -23.21N
F2X = 15.2N
F3X = -23.21N + 15.2N = -8.01N
F1Y = (26.8N)(0.5)
F1Y = 13.4N
F2Y = 0
F3Y = 13.4N + 0 = 13.4N
I found the components of F3X = -8.01 and F3Y = 13.4. When I plug the components into: F3= √F3X^2 + F3Y^2, I get 15.6115 N, which apparently is wrong. I've been on this problem forever and I don't know what I'm doing wrong.
As for this part of the question: "Specify the direction as a positive angle relative to the negative x axis, as shown in the figure." I am completely lost...
Thanks for any help.
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