Forces for Differing Masses and Accurately Reporting Them

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In summary: I think I understand what you're saying now. Basically, your equation is wrong because it is not accounting for the different forces the balls would experience due to their different masses. I've accounted for this in my report by including the ratio of bounce heights after each impact. In summary, Chet suggests that different masses would affect the force an object experiences when it is dropped, and that this should be accounted for in the report by reporting the ratio of bounce heights. This can be done by calculating the force based on the initial height and velocity of the object, and then reporting this in terms of height per unit of mass.
  • #1
KayCup
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Hey all,

I'm currently working on a chemistry lab report analyzing different ratios of reagents in polymers and their abilities to bounce. These different samples were dropped from a constant height and their bounces were recorded. I've calculated the force each struck the ground with.

My question is since different masses yield different forces, how should I account for this in my final report of bounce heights? What if I reported this in height per unit of mass? How can I analyze the effects of the ratios of reagents without influence from different forces?

I'd appreciate any direction someone could offer. :)
 
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  • #2
KayCup said:
Hey all,

I'm currently working on a lab report analyzing different ratios of reagents in polymers and their abilities to bounce. These different samples were dropped from a constant height and their bounces were recorded. I've calculated the force each struck the ground with.

My question is since different masses yield different forces, how should I account for this in my final report of bounce heights? What if I reported this in height per unit of mass? How can I analyze the effects of the ratios of reagents without influence from different forces?

I'd appreciate any direction someone could offer. :)

Welcome to Physics Forums!

Just report the ratio of the bounce heights for each material. This should be independent of the mass.

Incidentally, how did you calculate the force each struck the ground with?
 
  • #3
Thanks!

I'm sorry, I don't think I understand what you're saying. Why don't different masses affect the force?

I used F=KE/D, where D is the distance traveled after impact, or, in my case, how high the polymer ball bounced initially after impacting the ground. To calculate KE, I used: KE=1/2(mass*velocity), and velocity was V=square root(2*initial height*gravity)

So for my sample with mass of 1.85 g dropped from a height of 50 cm, with an initial bounce height of 1.85 cm, my force was 25.2 N.

If I'm doing something wrong, please tell me. Unfortunately, I haven't taken a physics class yet, so this is all information that I'm getting from the internet.
 
  • #4
Were you given permission to seek external help to do your lab report?

BTW, this should have been done in the HW/Coursework forum, where this thread will be moved to.

Zz.
 
  • #5
ZapperZ said:
Were you given permission to seek external help to do your lab report?

BTW, this should have been done in the HW/Coursework forum, where this thread will be moved to.

Zz.

In the information handout that we're given about the experiment, it encourages us to utilize resources available (i.e. book for the course, internet, etc.), and my TA suggested the tutoring center on campus for help. I'd go there now, but I'm not on campus at the moment, and I'd like to avoid working on this last minute.

Either way, sorry about using the wrong forum. I thought the HW forum was reserved specifically for physics classes.
 
  • #6
KayCup said:
Thanks!

I'm sorry, I don't think I understand what you're saying. Why don't different masses affect the force?

I used F=KE/D, where D is the distance traveled after impact, or, in my case, how high the polymer ball bounced initially after impacting the ground. To calculate KE, I used: KE=1/2(mass*velocity), and velocity was V=square root(2*initial height*gravity)

So for my sample with mass of 1.85 g dropped from a height of 50 cm, with an initial bounce height of 1.85 cm, my force was 25.2 N.

If I'm doing something wrong, please tell me. Unfortunately, I haven't taken a physics class yet, so this is all information that I'm getting from the internet.

I'm sorry, KayCup, but this is basically wrong. The equation for the force makes no sense.

If I understand what you are trying to do, you are trying to determine which formulation results in the highest elastic recovery (least dissipation of energy). To do this, you can take the ratio of the bounce height on subsequent bounces, including after you first release the ball. The closer this ratio is to 1.0, the higher the elastic recovery of energy. Properly determining the force (or really, the time variation of the force during contact with the ground) is a very complicated problem in deformational mechanics, including the so-called viscoelastic response behavior of the polymer.

I see from your data that, for example case you cited, the bounce height was only 1.85 cm for a drop height of 50 cm. This would only be a bounce ratio of 0.037, and would indicate a very large amount of energy dissipation, with not much elastic recovery. Are these figures correct? If you bounce a basketball, the bounce ratio will typically be on the order of 0.8, indicating a high degree of energy recovery.

Chet
 

FAQ: Forces for Differing Masses and Accurately Reporting Them

What is the concept of forces for differing masses?

The concept of forces for differing masses is based on Newton's Second Law of Motion, which states that the force applied to an object is directly proportional to its mass and acceleration. This means that objects with different masses will experience different forces when subjected to the same acceleration.

How do you accurately report forces for differing masses?

To accurately report forces for differing masses, it is important to use a standard unit of measurement, such as Newtons (N). This allows for consistency and comparability in reporting the forces. Additionally, it is important to clearly state the mass and acceleration of the objects involved in the force calculation.

What are some examples of forces for differing masses?

Some examples of forces for differing masses include a car accelerating with a heavier load in the back, a person pushing a shopping cart, and a rocket launching into space with varying amounts of fuel on board. In each of these scenarios, the force experienced by the object will vary based on its mass.

How does friction impact forces for differing masses?

Friction can impact forces for differing masses by adding an additional force that opposes the motion of the object. This can result in a difference in the overall force experienced by objects with different masses. For example, a heavier object may experience more friction when pushed along a surface than a lighter object, resulting in a different net force.

Why is understanding forces for differing masses important?

Understanding forces for differing masses is important because it allows us to accurately predict and explain the motion of objects in our daily lives. It is also crucial in fields such as engineering and physics, where precise calculations of forces are necessary for designing structures and predicting the behavior of objects under different conditions.

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