- #1
billybomb
- 9
- 0
Hi
So I'm trying to find out how much force a tin can, can support before failing. The can will be stood up as it should be with a force applied over the top across the area of the can.
I've tried the process of short column buckling to no avail.
I've also tried axial and hoop stress for thin walled pressurized vessels.
I keep getting silly numbers and am now completely lost.
Also, would you assume that pressure inside the can is the same as atmospheric?
So here are the numbers:
Length = 109mm
Diameter = 74mm
Assumed yield stress of 590n/mm^2
Atmospheric pressure = 0.101325n/mm^2
Any direction or help would put my mind at ease, thanks
I've found http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/19690013955_1969013955.pdf
Is page 14 the part I am look for?
Thanks again.
So I'm trying to find out how much force a tin can, can support before failing. The can will be stood up as it should be with a force applied over the top across the area of the can.
I've tried the process of short column buckling to no avail.
I've also tried axial and hoop stress for thin walled pressurized vessels.
I keep getting silly numbers and am now completely lost.
Also, would you assume that pressure inside the can is the same as atmospheric?
So here are the numbers:
Length = 109mm
Diameter = 74mm
Assumed yield stress of 590n/mm^2
Atmospheric pressure = 0.101325n/mm^2
Any direction or help would put my mind at ease, thanks
I've found http://ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/19690013955_1969013955.pdf
Is page 14 the part I am look for?
Thanks again.
Last edited: