- #1
austindubose
- 17
- 0
Homework Statement
Values from previous problem:
Pre-collision: v2kg=6m/s -->, v3kg=3m/s <--
Post-collision: v2kg=2m/s <--, v3kg=5.67m/s -->
Collision time: 0.2 sec
Homework Equations
F=mA=m(Δv/Δt)
The Attempt at a Solution
My instinct to solve this was to use the pre-collision values to find out the forces each puck had on each other, because it seems like post-collision values for velocity would be irrelevant because the pucks are no longer having any force on each other. So, I did the following...
Force of 2kg puck on 3kg puck: F=2kg(6m/s / 0.2 sec) = 60N
Force of 3kg puck on 2kg puck: F=3kg(3m/s / 0.2 sec) = 45N
Is this the correct way to approach this problem? Thanks for your help!