Forces- two pulleys w. diff accelerations

In summary, the problem involves a massless and frictionless system with a 10kg block and a 3kg block connected by a rope and pulleys. The goal is to find the tension in the rope and the acceleration of the 10kg block. The equations and free body diagrams are provided, but there may be a sign error in the equation for the 3kg mass. The acceleration of the 3kg mass is assumed to be half of the acceleration of the 10kg mass.
  • #1
Maiia
79
0

Homework Statement


In the drawing the rope and the pulleys are massless and frictionless, and there is no friction between the table and the block. Find the tension in the rope and the acceleration of the 10kg block.

Here is my drawing of the problem and my FBDs and equations.

problem2.jpg


I assumed that if the acceleration of the 10kg block was "L," the acceleration of the 3kg block would be 1/2 L because it is split between the two tensions...?

I would appreciate it if someone could check my work for this problem because I don't seem to be getting the right answer...
 
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  • #2
Hi Maiia,

Maiia said:

Homework Statement


In the drawing the rope and the pulleys are massless and frictionless, and there is no friction between the table and the block. Find the tension in the rope and the acceleration of the 10kg block.

Here is my drawing of the problem and my FBDs and equations.


I assumed that if the acceleration of the 10kg block was "L," the acceleration of the 3kg block would be 1/2 L because it is split between the two tensions...?

I would appreciate it if someone could check my work for this problem because I don't seem to be getting the right answer...

In your equation for the 3kg mass, you have:

[tex]
2T - F_g = \frac{3}{2} L
[/tex]
where L is the acceleration of the 10kg block. You seem to have a sign error here. Remember that everything with the same sign is going in the same direction, which would mean that this equation is saying the acceleration of the 3kg mass is in the same direction as the tension (and in the opposite direction of the force of gravity).
 
  • #3


Thank you for sharing your work and thought process on this problem. It is always helpful to see how others approach and solve physics problems.

From my understanding of the problem, it seems like you have correctly identified the forces acting on the system and set up the appropriate free body diagrams. However, I would like to clarify a few points to ensure accuracy in your solution.

Firstly, you are correct in assuming that the acceleration of the 3kg block would be half of the 10kg block's acceleration, as the tension in the rope is split between the two blocks. However, this does not necessarily mean that the acceleration of the 3kg block is 1/2 L. It would depend on the values of the tensions acting on the block.

Secondly, it is important to note that the tension in the rope is not the same throughout its length. In this case, the tension is different on either side of the pulleys due to the difference in the accelerations of the blocks. This is known as the "tension gradient" in the rope.

To accurately solve for the tension and acceleration of the 10kg block, you would need to set up and solve a system of equations using the Newton's second law for each block, taking into account the tension gradient in the rope. This would give you two equations with two unknowns (tension and acceleration). Solving these equations would give you the correct values.

I hope this helps in your understanding of the problem. Keep up the good work!
 

FAQ: Forces- two pulleys w. diff accelerations

What is the concept of forces in relation to two pulleys with different accelerations?

The concept of forces in this scenario refers to the tension forces acting on the two pulleys. When two pulleys with different accelerations are connected by a belt or rope, the tension forces on both sides of the belt or rope will be equal in magnitude but opposite in direction.

How does the acceleration of each pulley affect the tension forces?

The acceleration of each pulley affects the tension forces by influencing the amount of tension in the belt or rope. If one pulley has a higher acceleration than the other, the tension in the belt or rope will be greater on that side. This is because the greater acceleration requires a greater force to overcome the inertia of the object.

What is the relationship between the masses of the objects connected by the pulleys and the tension forces?

The relationship between the masses of the objects and the tension forces is indirect. The masses of the objects do not directly affect the tension forces, but they do affect the acceleration of the objects. The greater the mass, the greater the force needed to accelerate the object, thus resulting in a greater tension force in the belt or rope.

Can the tension forces in the belt or rope ever be greater than the weight of the objects?

Yes, it is possible for the tension forces in the belt or rope to be greater than the weight of the objects. This can happen if one of the objects has a greater acceleration than the other, resulting in a greater tension force on that side of the belt or rope.

How does the angle of the pulleys affect the tension forces?

The angle of the pulleys does not have a direct effect on the tension forces, but it can affect the direction and magnitude of the forces. For example, if the pulleys are not aligned in a straight line, the tension forces may have a horizontal and vertical component, resulting in a net force in a different direction.

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