Formally describe a Turing machine which decides if an input is odd or even.

In summary, a transition function for a Turing machine can be used to determine if a string of a's is odd or even by moving through a series of states and counting the number of moves. If the number of moves is even, the string is even, and if the number of moves is odd, the string is odd.
  • #1
JamesBwoii
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Hi, I need to use a transition function to describe a Turing machine that decides if $ a^n ∈ {a}^∗$ is odd or even.

I've got an example in my notes that erases any input and halts.

View attachment 3646

But I am struggling to do one for the odd and even question.

Thanks for any help!
 

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  • #2
The transition function for a Turing machine that decides if $a^n$ is odd or even can be described as follows:State 0 (start state): Read input character: If a, move one cell to the right and write a new a in the cell. Move to state 1.State 1: Read input character:If a, move one cell to the right and write a new a in the cell. Move to state 2.State 2: Read input character:If a, move one cell to the right and write a new a in the cell. Move to state 3.State 3: Read input character: If a, move one cell to the right and write a new a in the cell. Move to state 4.State 4: Read input character:If a, move one cell to the right and write a new a in the cell. Move to state 5.State 5: Read input character: If a, move one cell to the right and write a new a in the cell. Move to state 0 (end state).If n is even, the Turing machine will have a total of 2n moves, and will end in state 0. If n is odd, the Turing machine will have a total of 2n+1 moves, and will end in state 5.
 

FAQ: Formally describe a Turing machine which decides if an input is odd or even.

What is a Turing machine?

A Turing machine is a mathematical model that represents a hypothetical computing machine. It consists of a tape divided into cells, a read/write head that can move along the tape, and a finite set of states that determine the machine's actions. It is used to study the capabilities and limitations of computing machines.

How does a Turing machine decide if an input is odd or even?

To decide if an input is odd or even, a Turing machine must first read the input on its tape. It will then use its finite set of states and transition rules to manipulate the tape, moving the read/write head back and forth until it reaches the end of the input. If the final state of the machine is an accepting state, the input is considered to be even. If the final state is a rejecting state, the input is considered to be odd.

What is the input for a Turing machine that decides if a number is odd or even?

The input for a Turing machine that decides if a number is odd or even is a string of binary digits, representing the number to be checked. For example, the input "1101" would represent the number 13.

Are there different Turing machines for deciding odd or even for different number systems?

Yes, there can be different Turing machines for deciding odd or even for different number systems. The transition rules and states of the Turing machine would need to be adapted to work with the specific number system, such as binary, decimal, or hexadecimal.

Can a Turing machine decide if a number is odd or even for all possible inputs?

No, a Turing machine can only decide if a number is odd or even for inputs that can be represented on its tape. If the input is too large or complex, the Turing machine may not have enough tape or states to process it. Additionally, the Turing machine is limited to the rules and transitions programmed into it, so it may not be able to handle all possible inputs.

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