Formation of tetra ammine copper(ii) ion

In summary: Therefore, there is no possibility of sp3 hybridization in this case. As for the unoccupied p orbital, it is a vacant orbital as it does not contain any electrons, and this is possible due to the presence of the lone pair on the copper atom. In summary, the tetraammincopper(II) ion undergoes sp2d hybridization to achieve an octahedral geometry, and the unoccupied s and p orbitals are a result of this hybridization.
  • #1
Ekramul Towsif
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Homework Statement



I do not understand how in tetra amin copper(2) ion there happens the sp2d hybridization.I understand that the dsp2 hybridization seems unreasonable .But if the the electron of copper ion really needs to be in the last D orbital ,then why there can't happen sp3 hybridization?How can a P orbital be unoccupied by any electrons?One P is without any electrons!It all seems very headachely to me as I have got exams knocking at the door.PLAESE HELP ME WITH YOR BEST ANSWERS.

Homework Equations

The Attempt at a Solution

 
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  • #2
The tetraammincopper(II) ion has an octahedral structure with four nitrogen atoms as ligands and two water molecules occupying the axial positions. Therefore, it has a total of six groups (four N and two O) around the central copper atom. The electronic configuration of copper is 1s2 2s2 2p6 3s2 3p6 3d10 4s1.To achieve the octahedral geometry, the copper atom needs to undergo sp2d hybridization, which involves mixing one s orbital and two p orbitals with two d orbitals. This results in the formation of three sp2d hybrid orbitals, which are oriented towards the three nitrogen atoms, and three d orbitals, which are oriented towards the two oxygen atoms. The fourth s orbital remains unhybridized and is responsible for the lone pair on the copper atom. Since the s orbital is not hybridized, it does not participate in bonding and hence remains unoccupied.
 

Related to Formation of tetra ammine copper(ii) ion

1. What is the formation of tetra ammine copper(ii) ion?

The formation of tetra ammine copper(ii) ion refers to the chemical reaction in which a copper(ii) ion (Cu2+) is complexed with four molecules of ammonia (NH3) to form a stable, soluble complex with the chemical formula [Cu(NH3)4]2+. This process is also known as coordination or complex formation.

2. What is the role of ammonia in the formation of tetra ammine copper(ii) ion?

Ammonia plays a crucial role in the formation of tetra ammine copper(ii) ion as it acts as a ligand, which is a molecule or ion that binds to a central metal ion. In this case, ammonia molecules donate their lone pair of electrons to the copper(ii) ion, forming coordinate covalent bonds and stabilizing the complex.

3. What is the significance of the tetra ammine copper(ii) ion?

The tetra ammine copper(ii) ion is a significant complex in inorganic chemistry as it is a common example of a transition metal complex. It also has industrial applications, such as in the production of dyes and pigments, as well as in analytical chemistry for the determination of copper(ii) ions in solutions.

4. How is the tetra ammine copper(ii) ion formed?

The tetra ammine copper(ii) ion can be formed by the reaction of a copper(ii) salt, such as copper sulfate (CuSO4), with ammonia in aqueous or alcoholic solutions. The reaction is exothermic and can be easily observed by the color change from blue to deep blue or purple, indicating the formation of the complex.

5. What factors can affect the formation of tetra ammine copper(ii) ion?

The formation of tetra ammine copper(ii) ion can be affected by several factors, such as temperature, pH, and concentration of reactants. Higher temperatures and alkaline pH can favor the formation of the complex, while high concentrations of ammonia can lead to the formation of different copper-ammonia complexes. Additionally, the presence of other ions in the solution can also influence the formation of the tetra ammine copper(ii) ion.

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