- #1
ian2012
- 80
- 0
Consider a pendulum which is free to move in any direction and is sufficiently long and heavy that it will swing freely for several hours. Ignoring the vertical component both of the pendulum's motion and of the Coriolis force, the equations of motion for the bob are:
[tex]\ddot{x}=-\frac{g}{l}x+2(\omega)cos\theta\dot{y}[/tex]
[tex]\ddot{y}=-\frac{g}{l}y-2(\omega)cos\theta\dot{x}[/tex]
I've found these equations from 'Classical Mechanics - Kibble & Berkshire, 5th Edition'. I don't understand how they are derived?
[tex]\ddot{x}=-\frac{g}{l}x+2(\omega)cos\theta\dot{y}[/tex]
[tex]\ddot{y}=-\frac{g}{l}y-2(\omega)cos\theta\dot{x}[/tex]
I've found these equations from 'Classical Mechanics - Kibble & Berkshire, 5th Edition'. I don't understand how they are derived?