Four Equidistant Particles in electric fields

In summary, the net electric field produced by four particles forming a square with edge length a = 6.50 cm and charges q1 = 7.59 nC, q2 = -10.9 nC, q3 = 11.5 nC, and q4 = -6.06 nC at the square's center is 9064.45 N/C. This is found by calculating the electric field produced by each particle using the formula E = (kq)/r^2, converting the charges from nC to C and the distance from cm to m, and then adding the vectors of the electric fields produced by each particle.
  • #36
the thing is for the answer it says

Number: ____ N/C or V/m

and I cannot use vector letters, that's what is confusing me
 
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  • #37
yes, the question asks for the magnitude of the total field, which is of course a scalar (not a vector) …

you get this by adding the individual fields as vectors, so that gives you the a total vector, and then you write down the magnitude of that vector

(in our example, the total vector was 3i+4j, and so the magnitude was 5)
 
  • #38
ohhhhhhhhhhhh ok. This makes sense now. lol Thanks for your time and help. Physics is starting to make more sense now :smile:
 
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