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... and a prof of mine once said: A mathematician's talent is transmitted to his son-in-lawmathwonk said:mike is emil's son. (artin)
... and a prof of mine once said: A mathematician's talent is transmitted to his son-in-lawmathwonk said:mike is emil's son. (artin)
It seems to me that Dedekind cuts assume that you already know what addition is.fresh_42 said:Let ##C = ℝ## be the continuum and basis of the free abelian group ##F##. Further let ##ι : C → F## be the embedding (of the alphabet) and ##id: C → ℝ_+## the identity. Then there is a unique group homomorphism ##π: F → ℝ_+## which extends ##id##, i.e. ##id = π \, ι## because ##F## is free. ##π## is onto. The question is what kernel ##π## has or what makes ##4 + 5 = 9## since ##4 + 5## and ##9## are different elements in ##F##. The Dedekind cuts were what occurs to me. Maybe there is a more algebraic way to define the equivalence classes.
I thought one needs the order in ℝ and the embedding of ℚ. But you are right, this breaks the definition requirements only down on ℚ.lavinia said:It seems to me that Dedekind cuts assume that you already know what addition is.
micromass said:As for the addition structure on ##\mathbb{R}##. It might help to look at ##\mathbb{R}## as a ##\mathbb{Q}##-vector space of dimension ##2^{\aleph_0}##. So we could see it as something like ##\bigoplus_{2^{\aleph_0}~\text{factors}} \mathbb{Q}##