- #36
achap01
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so the ODE would be ẍ=a=-gx/R? Im a little confused
Yes, or to put it in its more standard form, ##\ddot x+\frac gRx=0##.achap01 said:so the ODE would be ẍ=a=-gx/R? Im a little confused
harmonic motion, so angular frequency (rate of oscillation) would be g/R, which have a derivative of 0 with respect to theta?haruspex said:Yes, or to put it in its more standard form, ##\ddot x+\frac gRx=0##.
Do you recognise that form?
Bingo.achap01 said:harmonic motion, so angular frequency (rate of oscillation) would be g/R, which have a derivative of 0 with respect to theta?
is there an online or a video proof of this that i can getharuspex said:Bingo.