- #1
nabet94
- 9
- 0
Homework Statement
a stone is thrown vertically upwards with a speed of u metres per second. a second stone is thrown vertically uppwards from the same point with the same initial speed but T seconds later than the first. prove that they collide at a distance (4u^2-g^2T^2)/(8g) metres above the point of projection.
Homework Equations
s=ut+.5(g)(t)^2
The Attempt at a Solution
now i should resolve vertically so i would get s= uT + .5(g)T^2 for the second and s= u(X-T)+ .5(g)(X-T)^2 for the first but when i attempt to get the answer i fail miserably or everything just cancels out. can someone help me with this?
Homework Statement
initial velocity is u and that time after second stone is thrown is T