Freight Wagons Collision: Calculating Speed, Acceleration & Force

In summary: The final velocity is given. So solve for it. v1 = (10000-15000)*2.0 ms-1 = 8000.0 ms-1v2 = (15000-10000)*2.0 ms-1 = 12000.0 ms-1So the final velocity of the collision is 8000.0 ms-1.
  • #1
ollieman
6
0

Homework Statement



An empty freight wagon of mass 10000kg rolls at 2.0 ms-1 along a level track and collides with a loaded wagon with a mass of 15000kg standing at rest with its breaks realized, If the wagons join together find.

a. their joint speed after the collision.

b. if the collision takes place in 0.1 seconds, what was the acceleration of the moving wagon during the collision

c. what was unbalanced force on the moving wagon during the collision?

d. What was the force on the moving wagon on the stationary wagon?

The Attempt at a Solution



I'm pretty sure the first question uses the law of conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

But i am just lost with what i need to substitute into this equation :(
 
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  • #2
ollieman said:

Homework Statement



An empty freight wagon of mass 10000kg rolls at 2.0 ms-1 along a level track and collides with a loaded wagon with a mass of 15000kg standing at rest with its breaks realized, If the wagons join together find.

a. their joint speed after the collision.

b. if the collision takes place in 0.1 seconds, what was the acceleration of the moving wagon during the collision

c. what was unbalanced force on the moving wagon during the collision?

d. What was the force on the moving wagon on the stationary wagon?

The Attempt at a Solution



I'm pretty sure the first question uses the law of conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

But i am just lost with what i need to substitute into this equation :(

Welcome to PF.

So what kid of collision do you think this is?
Elastic?
Or inelastic?
 
  • #3
LowlyPion said:
Welcome to PF.

So what kid of collision do you think this is?
Elastic?
Or inelastic?
Thanks for replying to my post LowlyPion

i haven't got any idea, it would be the most basic. Since this is my first year studying physics in a physical science course
 
  • #4
ollieman said:
Thanks for replying to my post LowlyPion

i haven't got any idea, it would be the most basic. Since this is my first year studying physics in a physical science course

In the equation you provided, any idea about what the terms are?
 
  • #5
[tex]\sum[/tex] Pi = [tex]\sum[/tex] Pf

From Newtons second law
 
  • #6
I understand what Conservation of momentum is thanks.

I was asking you what the terms were in the equation you wrote? What is m1 and u1 and ... etc.
 
  • #7
My text just says i can use either

m1u1 + m2u2 = m1v1 + m2v2

or

[tex]\sum[/tex] Pi = [tex]\sum[/tex] Pf
 
  • #8
ollieman said:
My text just says i can use either

m1u1 + m2u2 = m1v1 + m2v2

or

[tex]\sum[/tex] Pi = [tex]\sum[/tex] Pf

Yes the first is the two body form of the second.

Now what is m1 and m2 ?
What is u1 and u2 and v1 and v2?
 
  • #9
m1 mass of the first object
m2 mass of the second object
u1 initial velocity of the first object
u2 initial velocity of the second object
v1 final velocity of the first object
v2 final velocity of the first object

Sorry i just thought it was how it worked, but it must be only how I'm taught
 
  • #10
ollieman said:
m1 mass of the first object
m2 mass of the second object
u1 initial velocity of the first object
u2 initial velocity of the second object
v1 final velocity of the first object
v2 final velocity of the first object

Sorry i just thought it was how it worked, but it must be only how I'm taught

There you go. Good.

Now look at your problem and start assigning values. (Remember since it is inelastic you will have both final velocities equal.)
 
  • #11
I couldn't get it out right :s that's why i posted it on here
 
  • #12
ollieman said:
I couldn't get it out right :s that's why i posted it on here

They give you the mass of the 2 wagons. What do you figure those are then in the equation?

Plug them in.

The velocity of one of the wagons is given. Plug that in.

Then solve for the final velocity.
 

FAQ: Freight Wagons Collision: Calculating Speed, Acceleration & Force

How do you calculate the speed of a freight wagon collision?

To calculate the speed of a freight wagon collision, you need to know the distance traveled by the wagon before the collision, as well as the time it took for the collision to occur. You can then use the formula speed = distance/time to calculate the speed.

What factors affect the acceleration of a freight wagon during a collision?

The acceleration of a freight wagon during a collision is affected by several factors, including the mass and speed of the wagon, the mass and speed of the object it collides with, and any external forces acting on the wagon.

How do you calculate the force of a freight wagon collision?

The force of a freight wagon collision can be calculated using the formula force = mass x acceleration. You need to know the mass of the wagon, as well as the acceleration it experiences during the collision.

What units are typically used to measure speed, acceleration, and force in freight wagon collisions?

Speed is usually measured in meters per second (m/s) or miles per hour (mph). Acceleration is measured in meters per second squared (m/s^2) or feet per second squared (ft/s^2). Force is measured in Newtons (N) or pounds (lbs).

How can the calculations for freight wagon collisions be applied in real-world scenarios?

The calculations for freight wagon collisions can be used in various real-world scenarios, such as determining the safety of railway systems, predicting the potential damage and injuries from a collision, and optimizing the design of freight wagons to withstand collisions. These calculations are also important in accident investigations and determining liability in the event of a freight wagon collision.

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