Frequency applied to Cap & Inductor

In summary, the conversation discusses the application of 1kHz frequency to a 1000 μF capacitor and a 10 H inductor. The resulting capacitance for the capacitor is 1000 μF, while the reactance for the inductor is 62.8 kΩ. The solution for the reactance of the inductor is found using the equation Xl = 2∏FL.
  • #1
nightTerror
3
0
1. The problem statement

1kHz is applied to 1000 μF Capacitor, What is its Capacitance?
&
1kHz is applied to 10 H inductor, What is its reactance?

The Attempt at a Solution


using
x= -1/ωC = -1/2∏∫C
I came up with 159 fF

then for question 2 I got
using
Xl=2∏FL (better seen here http://www.raftabtronics.com/portals/0/EquationImages/XsubL.png )

and I got 62.8KΩ

my problem is this.
i tried learning it myself but this forum https://www.physicsforums.com/archive/index.php/t-35071.html confused me a little bit. So to make sure I am on the right path, I am posting on here yet again...and I am sure there will be more to come after this.
 
Last edited by a moderator:
Physics news on Phys.org
  • #2

FAQ: Frequency applied to Cap & Inductor

What is the relationship between frequency and capacitance?

The relationship between frequency and capacitance is inverse. As frequency increases, capacitance decreases, and vice versa. This means that a higher frequency signal will be able to pass through a lower capacitance capacitor more easily, while a lower frequency signal will be impeded by a higher capacitance capacitor.

How does frequency affect the impedance of a capacitor?

The impedance of a capacitor is directly proportional to the frequency of the signal passing through it. This means that as frequency increases, the impedance of the capacitor also increases. This is because at higher frequencies, the capacitor becomes less like an open circuit and more like a closed circuit, allowing more current to pass through.

What is the purpose of a capacitor in an AC circuit?

The purpose of a capacitor in an AC circuit is to store and release electrical energy. As the alternating current flows through the capacitor, it charges and discharges, smoothing out the signal and filtering out unwanted frequencies.

How does frequency affect the behavior of an inductor?

The behavior of an inductor is directly related to the frequency of the signal passing through it. At lower frequencies, an inductor acts as a short circuit, allowing current to flow through easily. However, at higher frequencies, the inductor becomes more like an open circuit, impeding the flow of current.

What is the formula for calculating the resonant frequency of an LC circuit?

The resonant frequency of an LC circuit can be calculated using the formula: f = 1/(2π√(LC)), where f is the resonant frequency in Hertz, L is the inductance in Henrys, and C is the capacitance in Farads.

Similar threads

Engineering Find di(0+)/dt and dv(0+)/dt of circuit containing resistor, inductor
Replies
3
Views
2K
Engineering Finals Study Time A Two Source Circuit w/Inductor, Cap, and Resistor
Replies
26
Views
3K
Engineering C = 10^-6Analyzing Parallel RLC Circuits: A Challenging Homework Problem
Replies
6
Views
2K
I How do I calculate the expected Gain?
Replies
1
Views
1K
Engineering What Is the Transfer Function H(ω) for This Circuit?
Replies
13
Views
3K
Engineering Calculate RLC Circuit Values: R1, R2, and Xl | Step-by-Step Guide
Replies
10
Views
4K
If R^2= L/C, show the total power is independent of frequency
Replies
5
Views
2K
The potential difference across an inductor
Replies
9
Views
10K
Engineering Magnitude versus Frequency Response Drawing from Pole-Zero Plot
Replies
8
Views
2K
How Does Frequency Affect C/N in Dish Antennas?
Replies
7
Views
1K

Hot Threads

Recent Insights

Back
Top