Frequency Spectrum of a Vibrating String

In summary, the conversation discusses the relationship between frequency and period in a sinusoidal function and the difference between frequency and natural frequency (eigenfrequency). The term "natural frequency" refers to resonance, while "frequency" refers to the frequency of the function. The conversation also explores the concept of angular frequency. Finally, it is mentioned that all values of $\displaystyle f_{n}=\frac{c\left(n + \frac{1}{2}\right)}{2L}$ are considered eigenfrequencies.
  • #1
Dustinsfl
2,281
5
Given $\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]$.

The period is $\tau = \frac{2L}{c\left(n + \frac{1}{2}\right)}$ so the frequency is $\frac{1}{\tau}$, correct?
 
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  • #2
Yes:

$\displaystyle f=\frac{1}{\tau}$
 
  • #3
MarkFL said:
Yes:

$\displaystyle f=\frac{1}{\tau}$

Is the period I obtained correct? Is that the yes or is the yes it is the reciprocal?
 
  • #4
If you have a function $\sin(kt)$, find the period $\tau$ by setting $k\tau=2\pi$.
 
  • #5
Sorry for being vague. :)

I agree with the period you found and with the relationship between frequency and period that you stated.

$\displaystyle \tau=\frac{2\pi}{\omega}$

In your case $\displaystyle \omega=\frac{\pi e}{L}\left(n+\frac{1}{2} \right)$

And so:

$\displaystyle \tau=\frac{2\pi}{ \frac{\pi e}{L} \left(n+ \frac{1}{2} \right)}= \frac{2L}{e\left(n+\frac{1}{2} \right)}$
 
  • #6
Ackbach said:
If you have a function $\sin(kt)$, find the period $\tau$ by setting $k\tau=2\pi$.
Is there a difference between frequency and natural frequency (eigenfrequencies)?
 
  • #7
dwsmith said:
Is there a difference between frequency and natural frequency (eigenfrequencies)?

The term "natural frequency" refers to resonance. So if you have a forced mass-spring system, e.g., and you tune the forcing function to the same frequency as a term in the homogeneous solution, you end up with unstable behavior.

The term "frequency" just refers to what's going on in this thread.

There's also the term "angular frequency", which is represented by $\omega=2\pi f$.

Hope that's as clear as mud.
 
  • #8
Ackbach said:
The term "natural frequency" refers to resonance. So if you have a forced mass-spring system, e.g., and you tune the forcing function to the same frequency as a term in the homogeneous solution, you end up with unstable behavior.

The term "frequency" just refers to what's going on in this thread.

There's also the term "angular frequency", which is represented by $\omega=2\pi f$.

Hope that's as clear as mud.

I am trying to find the natural frequency (eigenfrequency) of $u$.
How would I do that then?
$$
u(x,t) = \sum_{n = 1}^{\infty}\sin\left[\frac{\pi x}{L}\left(n + \frac{1}{2}\right)\right]\left\{A_n\cos\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right] + B_n\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]\right\}
$$
 
  • #9
dwsmith said:
I am trying to find the natural frequency (eigenfrequency) of $u$.
How would I do that then?
$$
u(x,t) = \sum_{n = 1}^{\infty}\sin\left[\frac{\pi x}{L}\left(n + \frac{1}{2}\right)\right]\left\{A_n\cos\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right] + B_n\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]\right\}
$$

Well, I could be wrong, but I would say that all of your
$$f_{n}=\frac{c\left(n + \frac{1}{2}\right)}{2L}$$
are the eigenfrequencies. I don't think there's one single eigenfrequency.
 

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