- #1
Dustinsfl
- 2,281
- 5
Given $\sin\left[\frac{\pi ct}{L}\left(n + \frac{1}{2}\right)\right]$.
The period is $\tau = \frac{2L}{c\left(n + \frac{1}{2}\right)}$ so the frequency is $\frac{1}{\tau}$, correct?
The period is $\tau = \frac{2L}{c\left(n + \frac{1}{2}\right)}$ so the frequency is $\frac{1}{\tau}$, correct?
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