MHB Friction on a half pipe in the middle location

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In a half pipe with a height L, the middle section has a friction coefficient of 0.1, while the rest is frictionless. The skateboarder starts with potential energy of Lmg and loses 0.1mgL of energy each time he crosses the frictional section. The energy loss leads to the equation Lmg = N(0.1mgL), allowing the calculation of the number of crossings. Solving this gives N = 10, indicating the skateboarder can go back and forth ten times before stopping. The discussion highlights the impact of friction on energy loss in a skateboarding scenario.
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Consider a half pipe of height L. The middle section, non sloping part, has a friction coefficient of \(\mu_k = 0.1\) and frictionless every where else. The length of this section is L. How many times can the skateboarder go back and forth before he stops?

In the friction section,
\[
\sum F_x = v_x - F_f = v_x - .1N
\]
since \(F_f = \mu_k N\).

Not sure how to determine how many times the skateboarder can go back and forth.
 
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Assume the skateboarder starts at the top L meter above the bottom with Lmg potential energy. When he crosses the bottom he always losses 0.1 mgL of energy no matter how high he had reached before. So having Lmg energy to start he can traverse the bottom N(0.1mgL) times.

Lmg = N(0.1mgL)

So N =10
 
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