Friction proportional to velovity. Help please

In summary, it takes the boat about 3 seconds to slow to one half its speed when the engine was shut off.
  • #1
ssm11s
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1. A 1000kg boat is traveling across a lake when its engine is shut off. The magnitude of the frictional force between the water and the boat is proportional to the boat's speed (proportionality constant is 70) . Find the time it takes the boat to slow to one half its speed when the engine was shut off.



2. We have to solve this problem using Newton's second law: F=ma



3. I thought about this problem for over a week now, and I really need all the help I can get!
 
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  • #2
first write the force as a constant times velocity, then equate with the acceleration equation you gave...

then do you know how to integrate?
 
  • #3
yes i know how to integrate but I am not quiet sure how to develop the integration. what should the variable be ?
 
  • #4
what did you get for the sum of your forces
 
  • #5
do you think there is an f app? or just friction force moving the boat. like a car on a road? i think it would be the same situation, do you?
 
  • #6
i think we use vfinal = v initial + at. as v/2= v + at. and a = (sum of forces divided by mass). i also think I am in your class.
 
  • #7
yeah i think there exists only a friction force. so the sum of forces would be : -f=ma

but the problem is the acceleration is not constant because the f is not constant
 
  • #8
so t = (v/2 + v)(1/a). and a = the 1st integral of v. and v= (frictional force/70) (is that right) but how do we get units in? and then frictinal force is the x component of the forces... but is there an f app?
 
  • #9
You said you know how to integrate so I assume you have taken Calculus. What would the force and acceleration not being constant bother you?

Use ma= f. What does that look like in this case? What is f? Do you understand that a= dv/dt?
 
  • #10
why didnt i think of that earlier. so dv/dt= -70v

divide both sides by v. then integrate one side in terms of dv and the other side in terms of t .
Thanks for the guidance !
 

FAQ: Friction proportional to velovity. Help please

What is the concept of "friction proportional to velocity"?

Friction proportional to velocity is a physical concept that states that the amount of friction between two surfaces is directly proportional to the velocity at which they are moving relative to each other. In other words, the faster the surfaces are moving, the greater the friction between them will be.

How does "friction proportional to velocity" affect the motion of objects?

This concept affects the motion of objects by slowing them down as their velocity increases. As the speed of an object increases, the amount of friction between the object and the surface it is moving on also increases. This results in a decrease in the object's velocity.

What are some real-life examples of "friction proportional to velocity"?

One example is the brakes on a car. As the car is moving at a high velocity, the brake pads are pressed against the wheels, creating friction and slowing down the car. Another example is the heat generated by rubbing your hands together quickly. The faster you rub your hands, the more friction is created, resulting in more heat.

How is "friction proportional to velocity" different from static friction?

Static friction is the force that prevents two stationary surfaces from sliding against each other. It is independent of velocity and only comes into play when there is no motion. On the other hand, friction proportional to velocity only applies to objects that are already in motion and increases as the velocity increases.

How does the surface material affect "friction proportional to velocity"?

The surface material plays a significant role in the amount of friction proportional to velocity that occurs. For example, a rough surface will create more friction than a smooth surface, even at the same velocity. This is because the rough surface has more surface area in contact with the moving object, resulting in more friction.

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