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brenfox
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frictional talk -- mass suspended from a flywheel
a mass of 0.5kg is suspended from a flywheel. if the mass is released from rest and falls a distance of 0.5m in 1.5sec calculate the frictional torque.
mass of wheel = 3kg
Radius= 0.3m
Radius of gyration = 0.212m
Torque = mk^2a
From a prevoius question i calculated the angular acceleration to be 1.48rads.
So torque= mk^2a = 3x0.212^2x1.48
So Torque = 0.2Nm if friction is ignored.
So i have a torque 0.2Nm and angular acceleration of 1.48rads^2
Am i right in thinking Torque-frictional torque= angular acceleration?
so 0.20- frictional torque = 1.48?. This doesn't seem to work out for me. any help would be appreciated
Homework Statement
a mass of 0.5kg is suspended from a flywheel. if the mass is released from rest and falls a distance of 0.5m in 1.5sec calculate the frictional torque.
mass of wheel = 3kg
Radius= 0.3m
Radius of gyration = 0.212m
Homework Equations
Torque = mk^2a
The Attempt at a Solution
From a prevoius question i calculated the angular acceleration to be 1.48rads.
So torque= mk^2a = 3x0.212^2x1.48
So Torque = 0.2Nm if friction is ignored.
So i have a torque 0.2Nm and angular acceleration of 1.48rads^2
Am i right in thinking Torque-frictional torque= angular acceleration?
so 0.20- frictional torque = 1.48?. This doesn't seem to work out for me. any help would be appreciated
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