From what height was the pot dropped at?

[Fentow]

Homework Statement

A falling flowerpot takes 0.2s to fall past a window which is 1.9m above ground. From what height was the pot dropped at?

Homework Equations

d = v1*t + (1/2)at^2

The Attempt at a Solution

I'm not sure what to do with the 1.9m above ground...

D = 0*0.2 + (1/2)(9.8m/s^2)(0.2)^2
D = 0.196

The book answer is 3.7m though, which is way off. I'm sure I have to use 1.9m to find the answer, but I'm at a loss right now. Help! Please and thank you!

 

[Chi Meson]

The flower pot has already been falling for some time before it passes the top of the window.

There are three things you know about this situation: acceleration, time to pass window, and vertical distance of window. What can this information tell you about how fast it was moving at the top of the window?

 

[ogb p]

Based on the given information, we can use the equation d = v1*t + (1/2)at^2 to find the initial height of the pot. The first step is to determine the initial velocity, v1. Since the pot is initially at rest, v1 = 0. Next, we can plug in the values for time (t = 0.2s) and acceleration (a = 9.8m/s^2) and solve for d.

d = (0)(0.2) + (1/2)(9.8m/s^2)(0.2)^2
d = 0 + 0.196
d = 0.196m

However, this only gives us the distance the pot has fallen in 0.2s. To find the initial height, we need to subtract this distance from the total distance the pot has fallen, which is 1.9m.

Initial height = 1.9m - 0.196m = 1.704m

Therefore, the pot was dropped from a height of 1.704m. It is important to note that this calculation assumes that the pot was dropped from rest and there was no air resistance. If these assumptions are not true, the calculated initial height may differ from the actual height.