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Homework Statement
Car (A) C180K WITH A 1.8 litre supercharged spark ignition, Maximum power output 104kw, based upon standard fuel efficiency test a vehicle with this engine would consume 6.1 liters over 100k journey
Car (B) C220 CDI with a 2.0 litre turbocharged diesel engine. Maximum output =109kw, based upon the standard fuel efficiency test a vehicle with this engine would consume 5.7 liters of Diesel over a 100km journey.
QUESTION: Calculate average fuel energy consumed per kilometer in the standard fuel efficiency test for each vehicle and hence determine which version of the vehicle had the most fuel efficient engine
Homework Equations
Convert miles per 100km to miles per gallon= 100*lpg/ kmpm*lp100km
lpg= litre per gallon= 4.54609188
kmpm= kilometers per mile= 1.609344
lp100km= litre per 100km
Variables given 1 mile = 1.609 km, 1 gallon = 4.546 litre
The Attempt at a Solution
Convert miles per 100km to miles per gallon= 100*lpg/ kmpm*lp100km
For Car A= 46.30 Car B = 49.56
Car (A) 104000 x 1800 = 187200000
187200000/ 1x10^6 =187.2
E gasoline = 187.2/(46.30 x 1.609km x 1/4.564)
E= gasoline= 11.47MJ/km < ANSWER
I DON'T WANT WASTE TIME ILL TRY CAR B WHEN I'M SURE MY STEPS ARE RIGHT FOR CAR A