Function growing faster than a sequence of functions

In summary, the conversation discusses finding a function that grows faster than any given sequence of functions f_k(n) from the naturals to itself. It is determined that it is not possible, but if the assumption of "pointwise bounded" is added, then it becomes possible. The process of constructing a sequence of polynomials to prove this is also discussed.
  • #1
simeonsen_bg
9
0
Hi, I have a sequence f_k(n) of functions N-->N, k=1,2... and I need to find a function f(n) growing faster than any f_k, i.e.

f_k(n)/f(n) --> 0 as n-->infinity for any k.

Is it possible and how can it be done?
 
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  • #2
Do you know anything about the f_k's?
 
  • #3
f_k are arbitrary functions from the naturals into itself.
 
  • #4
Ok, i realized that the following is wrong;

I'm pretty sure that it's not possible. I would first claim that for any function f: N -> N has a continuous extension. Then I would use the fact that polynomails are dense in the set of continuous functions on R. Since the set of polynomals are countable, I would construct a sequence of all polynomails. Then I would go to claim that there is no maximum continuous function (by saying suppose g is a maximum continuous function, then consider g + 1, kind of thing). So if I was given an continuous function, I would consider g + 1, and then find a polynomial that represents it arbitrarily close (at least with in 1/2 distance) and claim that g is indeed not a function that bounds my sequence of functions.

Ok. So now we've shown that in general it's impossible. However, if you add "poitwise bounded" as an assumption, then it is possible.
 
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FAQ: Function growing faster than a sequence of functions

What does it mean for a function to grow faster than a sequence of functions?

When a function grows faster than a sequence of functions, it means that the output of the function increases at a faster rate than the output of the sequence of functions as the input increases. This can also be interpreted as the function having a steeper slope or a higher degree of growth than the sequence of functions.

How can you determine if a function grows faster than a sequence of functions?

One way to determine if a function grows faster than a sequence of functions is to compare the growth rates at a specific input value. If the output of the function is larger than the output of the sequence of functions at that input value, then the function is growing faster.

What is the significance of a function growing faster than a sequence of functions?

A function growing faster than a sequence of functions can indicate a more rapid increase in values or quantities. This can have practical applications in fields such as physics, economics, and computer science.

Can a function grow faster than all possible sequences of functions?

Yes, it is possible for a function to grow faster than all possible sequences of functions. This is known as super-exponential growth and is often seen in functions with a factorial or exponential growth rate.

What is an example of a function that grows faster than a sequence of functions?

A commonly used example of a function that grows faster than a sequence of functions is the factorial function (n!). As n increases, the output of this function grows much faster than the output of a sequence of linear functions, such as f(n) = n or f(n) = 2n.

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