Function inside function proofe question

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If we negate the initial assumption instead, we are able to prove that g(x) is indeed monotonically increasing. In summary, it is given that f(x) is monotonically increasing and f(g(x)) is monotonically increasing. We can prove that g(x) is also monotonically increasing by using a proof by contradiction method.
  • #1
nhrock3
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it is given that f(x) is monotonically increasing and f(g(x)) is monotonically increasing

does g(x) is monotonically increasing??

i tried to solve it this way:

i think that it does.so i want to disprove the theory that g(x) is not is monotonically increasing:

suppose that g(x) is monotonically decreasing
if a<b then g(a)>g(b)
f(a)<f(b)
f(g(a))<f(g(b))

now what??
 
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  • #2
Suppose g(x) is monotonically decreasing. Let a<b. Then this means g(a)>g(b). Now since f(g(x)) is monotonically increasing, g(a)>g(b) must imply f(g(a))>f(g(b)). Notice the contradiction with one of our assumption? If not, examine the assumptions we made and the conclusion we ended up with.
 

FAQ: Function inside function proofe question

What is a function inside a function proof?

A function inside a function proof is a mathematical technique used to show that one function can be expressed as a composition of two or more functions. It involves substituting the inner function into the outer function and simplifying the resulting expression.

Why do we use function inside function proofs?

Function inside function proofs are useful for simplifying complex functions and understanding the relationships between different functions. They also allow us to solve more complicated problems by breaking them down into smaller, more manageable parts.

What are the key steps in a function inside function proof?

The key steps in a function inside function proof are: 1) identifying the inner and outer functions, 2) substituting the inner function into the outer function, 3) simplifying the resulting expression, and 4) showing that the original function can be expressed as a composition of the two functions.

Can a function inside function proof be used to prove the inverse function?

Yes, a function inside function proof can be used to prove the inverse function. By showing that a function can be expressed as a composition of two functions, we can also show that the inverse function exists and is equal to the composition of the inverse of the outer function and the inverse of the inner function.

Are there any limitations to function inside function proofs?

Function inside function proofs are limited to functions that can be expressed as a composition of two or more functions. They may also become more complex and difficult to solve for highly nested functions.

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