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Homework Statement
Solve:
$$\frac{\delta F[f]}{\delta f(x)}=b(x)f(x)^2F[f]$$
For b(x) a fixed smooth function.
Homework Equations
$$\left.\frac{dF[f+\tau h]}{d\tau}\right|_{\tau=0}\equiv \int\frac{\delta F[f]}{\delta f(x)}h(x)dx$$
The Attempt at a Solution
This isn't a homework problem since I'm self-studying this, but I don't know how to solve this equation. Based off of the analogy from regular ordinary differential equations, I tried the solution:
$$F[f(x)]=\int e^{b(x)f(x)^3/3}dx$$
So, constructing the function derivative, I start with:
$$F[f+\tau h]=\int e^{b(x)(f(x)^3+3f(x)^2\tau h(x)+3f(x)\tau^2 h(x)^2+\tau^3 h(x)^3)/3}dx$$
Taking the derivative, and then taking ##\tau\rightarrow 0## I get:
$$\left.\frac{dF[f+\tau h]}{d\tau}\right|_{\tau=0}=\int \left(b(x)f(x)^2e^{b(x)f(x)^3/3}\right)h(x)dx$$
Therefore:
$$\frac{\delta F[f]}{\delta f(x)}=b(x)f(x)^2e^{b(x)f(x)^3/3}$$
This almost looks right except there's no integral over the exponential term, so that term is not F[f]...I feel like this is close, but certainly not right.
I don't know any other method of trying to solve this problem. Thanks.