Functions of Several Variables, Temperature?

In summary, the conversation was about a student named Calleigh who was new to the forum and had some questions about a Calculus problem involving temperature and heat. The problem asked to find the directions of no change in heat and the direction of greatest increase in heat from a given point on a metal plate. The conversation included discussions about taking the derivative of a function with two variables, using the gradient and directional derivative, and consulting a textbook for a fuller treatment of the topic. In the end, the student was able to find the correct solutions for the problem.
  • #1
CalleighMay
36
0
Hello, my name is Calleigh and i am new to the forum! I am in Calculus II and have a few questions on some problems. I am using the textbook Calculus 8th edition by Larson, Hostetler and Edwards. Could someone please help me?

The problem is on pg 942 in chapter 13.6 in the text, number 76. It reads:

The temperature at point (x,y) on a metal plate is modeled by:
T(x,y)=400e^-((x^2+y)/2) where x>=0 and y>=0.

It asks to find the directions of no change in heat on the plate from the point (3,5).
It also asks to find the direction of greatest increase in heat from the point (3,5).


Does anyone know what this problem is talking about? Usually it helps if i can picture it in my head but I'm lost... My professor suggested drawing a picture, but i haven't the slightest clue even where to begin.

Any help would be greatly appreciated! Thanks guyssss ;)
 
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  • #2
CalleighMay said:
Hello, my name is Calleigh and i am new to the forum! I am in Calculus II and have a few questions on some problems. I am using the textbook Calculus 8th edition by Larson, Hostetler and Edwards. Could someone please help me?

The problem is on pg 942 in chapter 13.6 in the text, number 76. It reads:

The temperature at point (x,y) on a metal plate is modeled by:
T(x,y)=400e^-((x^2+y)/2) where x>=0 and y>=0.

It asks to find the directions of no change in heat on the plate from the point (3,5).
It also asks to find the direction of greatest increase in heat from the point (3,5).


Does anyone know what this problem is talking about? Usually it helps if i can picture it in my head but I'm lost... My professor suggested drawing a picture, but i haven't the slightest clue even where to begin.

Any help would be greatly appreciated! Thanks guyssss ;)
If you are looking for the direction in which there is no change in temperature*, what can you say about the directional derivative in that direction?

For the second part, what does the gradient of a vector field represent?

(*)From a physics point of view, I will mention that temperature and heat are not the same thing, but since we're in Maths, I'll let you off :wink:.
 
  • #3
thanks for the reply hootenanny!

So you're saying i should take the derivative of T(x,y)? How do i do that with 2 variables in the parenthesis?
 
  • #4
Someone suggested a different method and i gave it a shot, could someone tell me if this is right?

-400xe^-((x^2+y)/2), p=-1200e^-7
400(-.5)e^-((x^2+y)/2), p=200e^-7
-200e^-7 (6,1)

Now, i have no idea what this means, i just followed the example and did the same thing. Can anyone understand this and tell me if its right? lol Thanks ;)
 
  • #5
CalleighMay said:
thanks for the reply hootenanny!

So you're saying i should take the derivative of T(x,y)? How do i do that with 2 variables in the parenthesis?
You're studying multi variable calculus, you must know how to take the gradient and determine the directional derivative of a function.
CalleighMay said:
Someone suggested a different method and i gave it a shot, could someone tell me if this is right?

-400xe^-((x^2+y)/2), p=-1200e^-7
400(-.5)e^-((x^2+y)/2), p=200e^-7
-200e^-7 (6,1)

Now, i have no idea what this means, i just followed the example and did the same thing. Can anyone understand this and tell me if its right? lol Thanks ;)
I honestly have no idea what you have done here.
 
  • #6
Then can you start me off in the right direction? My friends and are are tying these out, we honestly don't know what to do. We haven't covered this stuff in class yet our professors just giving us a peak at what w will encounter in next semester, i just want to impress him.
 
  • #7
Then impress him by looking up "gradient" or "gradient vector" in your textbook.
 
  • #8
CalleighMay said:
Then can you start me off in the right direction? My friends and are are tying these out, we honestly don't know what to do. We haven't covered this stuff in class yet our professors just giving us a peak at what w will encounter in next semester, i just want to impress him.
If you click on the words gradient and directional derivative you'll be taken to the appropriate articles in our Library. However, these only offer a brief overview. For a fuller treatment I suggest that you consult your text.

Have you done any partial differentiation yet?
 
  • #9
Thanks for those links they help a little. I actually found an example that seemed to ask for the same things, so i tried the method on this prob and this is what i got...

T(x,y)= 400e^-((x^2+y)/2) [-xi-(1/2)j]
T(3,5)=400e^(-7[-3i-(1/2)j)]

So there will not be change in directions perpendicular to the gradient +or - (i-6j)

and the largest increase will be in the direction of the gradient -3i-(1/2)j

does this seems about right? thanks ;)
 
  • #10
CalleighMay said:
Thanks for those links they help a little. I actually found an example that seemed to ask for the same things, so i tried the method on this prob and this is what i got...

T(x,y)= 400e^-((x^2+y)/2) [-xi-(1/2)j]
T(3,5)=400e^(-7[-3i-(1/2)j)]

So there will not be change in directions perpendicular to the gradient +or - (i-6j)

and the largest increase will be in the direction of the gradient -3i-(1/2)j

does this seems about right? thanks ;)
Looks good to me :approve:.
 
  • #11
thanks! :)
 

FAQ: Functions of Several Variables, Temperature?

What is the definition of a function of several variables?

A function of several variables is a mathematical concept in which the output of the function depends on multiple independent variables. It is often represented by f(x,y,z) where x, y, and z are the independent variables and f is the dependent variable.

How does temperature affect a function of several variables?

Temperature can affect a function of several variables in multiple ways. It can be one of the independent variables that the function depends on, or it can be a factor that influences the output of the function. For example, in a chemical reaction, temperature can affect the rate of reaction which is a function of multiple variables such as concentration, pressure, and temperature.

What is the role of partial derivatives in functions of several variables?

Partial derivatives are used to determine how a function of several variables changes when one independent variable is varied while holding the others constant. They are important in understanding the sensitivity of the function to each variable and can help in optimization and finding critical points.

What are some real-life applications of functions of several variables?

Functions of several variables have a wide range of applications in fields such as physics, chemistry, engineering, and economics. They are used to model complex systems and phenomena such as heat transfer, fluid dynamics, chemical reactions, and financial markets. They also play a crucial role in optimization and decision-making processes.

How is the temperature distribution in a three-dimensional object represented mathematically?

The temperature distribution in a three-dimensional object can be represented using a function of three variables, f(x,y,z). Each point (x,y,z) in the object corresponds to a specific temperature value, and the function describes the relationship between these variables. It can be visualized using contour plots or three-dimensional graphs.

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