- #1
JoeyBob
- 256
- 29
- Homework Statement
- See attached
- Relevant Equations
- F=qE, F=qv cross product B
So I know the acceleration is 0, so the net force is 0.
QE=1.6E-3*9.9E3 k hat = 15.84 k hat (thats one force)
qv x B = q(v i hat + v j hat) x (0.51 i hat + 0.10 j hat)
=q(0.10 v k hat- 0.51 v k hat)
=q(-0.41 v k hat)
=-0.000656 v k hat
Now solving for velocity,
0.000656v=15.84, v=24146.34146
The question says I need to find the ratio, and I know vy is .41 times higher, so i multiply by this to get 9890.
This answer is wrong, it should be -3665.31.
QE=1.6E-3*9.9E3 k hat = 15.84 k hat (thats one force)
qv x B = q(v i hat + v j hat) x (0.51 i hat + 0.10 j hat)
=q(0.10 v k hat- 0.51 v k hat)
=q(-0.41 v k hat)
=-0.000656 v k hat
Now solving for velocity,
0.000656v=15.84, v=24146.34146
The question says I need to find the ratio, and I know vy is .41 times higher, so i multiply by this to get 9890.
This answer is wrong, it should be -3665.31.