- #1
jsalapide
- 40
- 0
1.Calculate the fundamental frequency of a steel rod of length 2.00 m. What is the next possible standing wave frequency of this rod? Where should the rod be clamped to excite a standing wave of this frequency?
first, i used the formula velocity of sound in the rod v=sqrt(Y/p)
where Y=20x10^10 Pa and p=7800 kg/m^3
i got 5063.7 m/s
then i substitute it to the formula for frequency f=v/4L
where L is the length of the rod..
my answer was 632.96 Hz
is that correct?
i cannot answer the succeeding questions.. please help..
first, i used the formula velocity of sound in the rod v=sqrt(Y/p)
where Y=20x10^10 Pa and p=7800 kg/m^3
i got 5063.7 m/s
then i substitute it to the formula for frequency f=v/4L
where L is the length of the rod..
my answer was 632.96 Hz
is that correct?
i cannot answer the succeeding questions.. please help..