- #1
Monobrow
- 10
- 0
Suppose we have a group with presentation G = <A|R> i.e G is the quotient of the free group F(A) on A by the normal closure <<A>> of some subset A of F(A). Is it true that that fundamental group of the Cayley graph of G (with respect to the generating set A) will be isomorphic to the subgroup <<A>> in F(A)? It seems to me that this should be true (and it agrees with the facts that: a subgroup of a free group is free and the fundamental group of a graph is free) but I can't find this theorem stated anywhere...