- #1
member 731016
- Homework Statement
- In my lecture notes I have ##Φ'(t) = AΦ(t) ⟷ x'(t) = Ax##. I am trying to understand why.
- Relevant Equations
- ##Φ'(t) = AΦ(t) ⟷ x'(t) = Ax##
My working is ,
Consider case where the there are two linearly independent solutions
##x'(t) = c_1x' + c_2y' = A(c_1x + c_2y)##
##(x'~y')(c_1~c_2)^T = A(x~y)(c_1~c_2)^T##
Then cancelling coefficient matrix I get,
##(x'~y')= A(x~y)##
##Φ'(t) = AΦ(t) ## by definition of 2 x 2 fundamental matrix
Does someone please know whether this proof is correct?
Thanks!
Consider case where the there are two linearly independent solutions
##x'(t) = c_1x' + c_2y' = A(c_1x + c_2y)##
##(x'~y')(c_1~c_2)^T = A(x~y)(c_1~c_2)^T##
Then cancelling coefficient matrix I get,
##(x'~y')= A(x~y)##
##Φ'(t) = AΦ(t) ## by definition of 2 x 2 fundamental matrix
Does someone please know whether this proof is correct?
Thanks!