Fundemental theorem of Calc. question?

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In summary, the conversation involves finding a function f(x) and constant a such that 6+ integral f(t)/t^2 dt = 2x with limits from a to x. The solution involves setting x = a and finding that a = 3, and then using the fundamental theorem to solve for f(x) as 2x^2 - 6. There is also a suggestion to take the derivative of both sides to check the solution, which leads to the conclusion that the derivative of 6 is 0.
  • #1
Integral8850
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Homework Statement


Find function f(x) and constant a such that,

6+ integral f(t)/t^2 dt = 2x
limits are a to x

Homework Equations


I think I am on the right track could someone check this?

The Attempt at a Solution


if x = a then the integral will = 0,
6 = 2a, a = 3 limits now are 3 to x,
now,
6 + integral f(x)/x^2 dx = 2x, fundamental theorem
6 + f(x)/x^2 = 2 => 6 + f(x)= 2x^2 => f(x)= 2x^2 - 6
Thanks!
 
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  • #2
try to take the derivative of both sides and see what happens?
on your last line, when you took the derivative, you missed something. what is the derivative of 6?
 
  • #3
Ok thanks that was the part I was not sure about so the derivative of 6 goes to 0.
Thanks!
 

FAQ: Fundemental theorem of Calc. question?

What is the fundamental theorem of calculus?

The fundamental theorem of calculus is a theorem that connects the concepts of differentiation and integration. It states that the integral of a function can be calculated by evaluating its antiderivative at the upper and lower limits of integration.

What are the two parts of the fundamental theorem of calculus?

The first part, also known as the fundamental theorem of calculus (FTC) Part 1, states that if a function is continuous on a closed interval, then the definite integral of that function over that interval can be calculated by finding an antiderivative of the function and evaluating it at the upper and lower limits of integration.

The second part, or FTC Part 2, states that if a function is differentiable on an open interval, then the derivative of its definite integral is equal to the original function.

How is the fundamental theorem of calculus applied in real-life situations?

The fundamental theorem of calculus has many practical applications, such as calculating areas, volumes, and other quantities in physics, engineering, and economics. It also plays a crucial role in the development of other mathematical concepts, such as differential equations and optimization problems.

Is the fundamental theorem of calculus only applicable to continuous functions?

Yes, the fundamental theorem of calculus is only applicable to continuous functions. This is because the theorem relies on the property of continuity to ensure that the function has a well-defined antiderivative.

Are there any limitations to the fundamental theorem of calculus?

The fundamental theorem of calculus has certain limitations, such as the requirement for the function to be continuous and differentiable on a given interval. It also assumes that the function has a well-defined antiderivative, which may not always be the case. Additionally, the theorem may not apply to functions with discontinuities or infinite discontinuities.

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