- #1
kakarukeys
- 190
- 0
why G parity = [tex](-1)^I C[/tex]?
C is the Charge conjugation number of the neutral member.
G parity of [tex]\pi^0[/tex] is very obvious. Given [tex]e^{i\pi I_2} |I\ 0\rangle = (-1)^I |I\ 0\rangle[/tex]
How do you compute the G parity of [tex]\pi^+[/tex]?
G parity operator
[tex]G = Ce^{i\pi I_2}[/tex]
C is the Charge conjugation number of the neutral member.
G parity of [tex]\pi^0[/tex] is very obvious. Given [tex]e^{i\pi I_2} |I\ 0\rangle = (-1)^I |I\ 0\rangle[/tex]
How do you compute the G parity of [tex]\pi^+[/tex]?
G parity operator
[tex]G = Ce^{i\pi I_2}[/tex]