- #1
mune
- 19
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Hi all,
Let's say we have 2 closed cylinders A and B, same volume, containing air inside. Two cylinders are connected to each other with a tube, with valve. Initially the valve is closed.
cylinder A: P=100 Pa, T= 350 k.
cylinder B: P=50 Pa, T= 300 k
now if the valve is opened, and closed when their pressure are the same.
assume no heat loss to or gain from surrounding.here my problem:
will their temperature be the same when their reach the same pressure?
my guess are...
1. yes. By ideal gas law, PV/T = mR, if P1=P2, V1=V2, then T1=T2, so the temp will be the same.
2. no. When the valve is opened, the air flows from A to B, which means the air does some flow work. By conservation of energy, the temp in B will be higher than A.
which one of me should I believe??
thanks.
Let's say we have 2 closed cylinders A and B, same volume, containing air inside. Two cylinders are connected to each other with a tube, with valve. Initially the valve is closed.
cylinder A: P=100 Pa, T= 350 k.
cylinder B: P=50 Pa, T= 300 k
now if the valve is opened, and closed when their pressure are the same.
assume no heat loss to or gain from surrounding.here my problem:
will their temperature be the same when their reach the same pressure?
my guess are...
1. yes. By ideal gas law, PV/T = mR, if P1=P2, V1=V2, then T1=T2, so the temp will be the same.
2. no. When the valve is opened, the air flows from A to B, which means the air does some flow work. By conservation of energy, the temp in B will be higher than A.
which one of me should I believe??
thanks.