- #1
FS98
- 105
- 4
To find the electric field from an infinitely long charged rod you can use gauss’s law with a cylinder as your Gaussian surface. I don’t quite understand by this works. Wouldn’t the electric field given by the equation only be the electric field cause by the charge within the cylinder? And if that’s the case, how could gauss’s law describe the charge of an infinite rod with a Gaussian cylinder of finite size?