- #1
Barry Johnston
Homework Statement
Gaussian beam of radius R_i and beam width w_i, The beam is reflected off a mirror with a radius of curvature R = R_i and the reflectivity of this mirror is given as rho(r) = rho_0*exp(-r^2/a^2), where r is the radial distance from the center of the mirror and a is a constant. Derive an expression for the modified beam width after reflection. Assumed that we are in air, ideal conditions, and we are talking about the fundamental TEM(0,0) mode.
Homework Equations
Electric field (propogation along z) E(x,y,z) = E_0*(w_0/w(z))*exp(-j*(k*z-nu(z)-(k*r^2/2*R(z)))*exp(-r^2/w(z)^2)
where k = 2*Pi*n/Lambda
Radius of curvature, R(z) = z*(1+z_0^2/z^2)
phase parameter, nu(z) = tan^-1(z/z_0)
Rayleigh range, z_0 = Pi*n*w_0^2/Lambda
beam width, w(z) = w_0*(1+z^2/z_0^2)^(0.5)
w_0 = initial beam width
The Attempt at a Solution
I have attempted to solve this problem by taking the square root of the reflectivity to get the Fresnel reflection coefficient. I then multiplied this by the electric field and tried to solve for a new initial beam waist so that I could plug this into the beam width express w(z). The initial beam waist is found by setting z = 0 and solving for the real part of the exponential exponent being equal to -1 (where r = w_0 in this case). I know that since the reflectivity of the mirror is equal to a Gaussian, we would expect the reflected beam width to decrease since we are taking a Gaussian of a Gaussian beam. So far I get nowhere near the results expected, I would appreciate any help to put me in the right direction, thanks!