Gaussian wavefunction; expectation energy

In summary, the problem is to solve for <H> using the operator, but there is a quicker method that the person is not able to figure out. The suggestion is to use the definition of <H> and the given operator, keeping in mind that p is proportional to the partial derivative with respect to x in the position representation.
  • #1
novop
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Homework Statement



2i77ebs.jpg

Homework Equations


The Attempt at a Solution



The issue I'm having here is that the problem should be able to be done rather quickly. I can see how to solve for <H> using the operator, but there's a quick way that I'm not picking up on.

I thought about solving <H> = <p^2> / 2m, but getting <p^2> is just as much of a pain.

Any help ?
 
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  • #2
By definition,

[tex]\langle H \rangle = \int \psi^* \hat H \psi \, dx[/tex]
where, as you said
[tex]\hat H = \frac{p^2}{2m}[/tex]

and you should be able to do that using the second hint (remember that [itex]p \propto \partial/\partial x[/itex] in the position representation).
 

FAQ: Gaussian wavefunction; expectation energy

What is a Gaussian wavefunction?

A Gaussian wavefunction is a mathematical function used to describe the probability distribution of a quantum particle in space. It is often used to represent the electron density in an atom or molecule.

How is a Gaussian wavefunction related to the expectation energy?

The expectation energy is the average energy that a particle would have if it were in a particular state described by the wavefunction. In the case of a Gaussian wavefunction, the expectation energy is directly related to the position of the particle and can be calculated using the Schrӧdinger equation.

Can a Gaussian wavefunction be used to describe all types of particles?

No, a Gaussian wavefunction is specifically used to describe quantum particles, such as electrons, in a probabilistic manner. It cannot be used to describe classical particles, such as those in Newtonian physics.

How is the normalization of a Gaussian wavefunction important?

The normalization of a Gaussian wavefunction ensures that the total probability of finding a particle in all possible positions is equal to 1. This is a necessary condition for probability distributions and ensures that the wavefunction accurately describes the behavior of the particle.

Are there any limitations to using a Gaussian wavefunction?

Yes, there are some limitations to using a Gaussian wavefunction. It assumes that the potential energy is constant, which is not always the case in real systems. Additionally, it cannot accurately describe systems with multiple particles or interactions between particles.

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