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coffeecat91
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Homework Statement
Calculate the mass of nitrogen dissolved at room temperature in an 80.0L home aquarium. Assume a total pressure of 1.0 atm and a mole fraction for nitrogen of .78.
Homework Equations
Mole fraction= moles solute/moles solution
Sgas=KH x Pgas
KH = 6.1 x 10-4 M/atm
The Attempt at a Solution
Sgas = (6.1 x 10-4)(1 atm)
Sgas = 6.1 x 10-4
6.1 x 10-4/ 1 L x 80.0 L = 4.88 x 10-2 moles
(4.88 x 10-2 moles) x 28.02 g Ns/ 1 mol = 1.37 g N2
the correct answer is 1.1 g N2
Where did I go wrong and where does the mole fraction bit come into play? Thanks!