Okay I mapped sinx and got:
2sin^{2}x-3sinx+sinx=0
(2sinx-1)(sinx-1)=0
2sinx=1 or sinx=1
sinx=1/2p
DERRAN said:Thanks for helping
The equation "2sinx + cosecx - 3 = 0" is a general equation that represents a relationship between the sine and cosecant functions with a constant value of -3.
The general solution to "2sinx + cosecx - 3 = 0" is a set of values for x that satisfy the equation. In this case, the general solution is x = 2nπ ± π/6, where n is any integer.
To solve "2sinx + cosecx - 3 = 0" algebraically, you can use trigonometric identities to rewrite the equation as (2sinx - 3)(cosecx - 1) = 0. From here, you can solve for each factor separately to find the general solution.
The possible values for x in "2sinx + cosecx - 3 = 0" are all real numbers that satisfy the equation. However, since the cosecant function is undefined at x = 0, the solutions must exclude x = 0.
The graph of "2sinx + cosecx - 3 = 0" is a combination of the sine and cosecant functions, resulting in a series of curves that intersect at certain points. The graph is symmetrical about the line x = π/2 and has asymptotes at x = 0 and x = π.