- #1
Superposed_Cat
- 388
- 5
Hey all, I had this problem the other day, I had to find the generel solution of cos^2x+sinx=1 what I did was:
Sinx=1-cos^2x
Sinx=sin^2x
-sin^2x+sinx=0
(-Sinx-1)(sinx+0)=0
Sinx=0 or 1 so x=90+360n or x=0+360n but the textbook says "n/a and 90+360n" without showing any working out. Any help apreciated, apologies if this isn't the right thread but this isn't homework and there didn't seem to be a section for this under the homework anyway.
Sinx=1-cos^2x
Sinx=sin^2x
-sin^2x+sinx=0
(-Sinx-1)(sinx+0)=0
Sinx=0 or 1 so x=90+360n or x=0+360n but the textbook says "n/a and 90+360n" without showing any working out. Any help apreciated, apologies if this isn't the right thread but this isn't homework and there didn't seem to be a section for this under the homework anyway.