- #1
AN630078
- 242
- 25
- Homework Statement
- Hello, I have been practising arithmetic and geometric sequences when I came across the problem below but I am not sure whether I have arrived at the correct conclusion, since the values I have determined for the first few terms in the sequence do not have a constant common ratio as defined by un+1/un=r. Have I made a mistake in my calculations?
1. Find the values of u2,u3 and u4 given tht un+1=3-1/3(un) and u1=3
2. Find the limiting value of un as n tends to infinity
- Relevant Equations
- un+1=3-1/3(un)
1. When n=1,
u1+1=3-1/3(u1)
u2=3-1/3(3)
u2=2
When n=2
u2+1=3-1/3(u2)
u3=3-1/3(2)
u3=7/3
When n=3
u3+1=3-1/3(u3)
u4=3-1/3(7/3)
u4=20/9
The common ratio is defiend by r=un+1/un, but this is different between the terms, i.e. u2/u1=2/3 whereas u3/u2=(7/3)/2=7/6
Have I made a mistake?
2. A sequence u1, u2, u3... converges to a limit L as the terms get ever closer to L. If the limit of un as n → ∞ is L, the terms un and un+1 are approximately equal to L.
un+1=3-1/3(un)
Replace un+1 and un with L in the equation.
L=3-1/3L
4/3L=3
4L=9
L=9/4
Thus, the limiting value of the sequence is 9/4. Would this be correct?
u1+1=3-1/3(u1)
u2=3-1/3(3)
u2=2
When n=2
u2+1=3-1/3(u2)
u3=3-1/3(2)
u3=7/3
When n=3
u3+1=3-1/3(u3)
u4=3-1/3(7/3)
u4=20/9
The common ratio is defiend by r=un+1/un, but this is different between the terms, i.e. u2/u1=2/3 whereas u3/u2=(7/3)/2=7/6
Have I made a mistake?
2. A sequence u1, u2, u3... converges to a limit L as the terms get ever closer to L. If the limit of un as n → ∞ is L, the terms un and un+1 are approximately equal to L.
un+1=3-1/3(un)
Replace un+1 and un with L in the equation.
L=3-1/3L
4/3L=3
4L=9
L=9/4
Thus, the limiting value of the sequence is 9/4. Would this be correct?