naren11 said:
dextercioby said:The formula they gave looks weird...That [itex] \vartheta_{2} [/itex] is written as a function of [itex] \vartheta_{1} [/itex] & [itex] \cos\vartheta_{2} [/itex]
Since the problem reminds somehow of the classical HS theory of Compton effect,i assume that [itex]\vartheta_{2} [/itex] can be found exactly...
Daniel.
). The formula i get has a v1' and a cosine of theta_1, instead of v1 * cos(theta2). It seems quite stupid to me that we'd set up a formula for theta 2 that actually contains the theta2A collision in physics is an event in which two or more objects come into contact with each other and exert forces on each other for a short period of time. This can result in a change in motion or deformation of the objects involved.
In an elastic collision, the total kinetic energy of the system is conserved, meaning that the objects involved bounce off each other without losing any energy. In an inelastic collision, some of the kinetic energy is lost and converted into other forms of energy, such as heat or sound.
Momentum is conserved in a collision because of Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. This means that the total momentum before and after the collision must be the same.
The force of impact in a collision can be calculated using the formula F = m x Δv / Δt, where F is the force, m is the mass of the object, Δv is the change in velocity, and Δt is the time of impact.
Impulse is the change in momentum of an object and is equal to the force applied to the object multiplied by the time over which the force is applied. In a collision, the impulse can be calculated by multiplying the average force of impact by the time of impact.