Get the resistance for each wires

[Izekid]

One day when the familiy Jones is out and drives with his new car wonders Oskar why there is a lot of wires in the backwindow. The heat wires are parallelwired where the resistance is resistance free wired.
Oskar and his father reads in the instructionsbook that the wires got a resistance 5.0ohm/m they are connected six times parallely and the length of each wire is 0.8 m

Then I get the resistance for each wires is 0.8*5 = 4 Ohm

But This is not the answer, the book says that the answer should be 6Ohm because two wires creates a parallelwiring with resistance 4 Ohm in every turn and 2Ohm as replacementresistance

Can someone please explain to me how to do this ? :zzz: :zzz: :zzz: :zzz:

Im really stuck...

Thx

 

[Integral]

I do not understand the statement of your problem.

Post your native language, perhaps there is someone here who could help you get a better translation.

 

[quicknote]

Dear Oskar and family Jones,

It seems like you are trying to calculate the resistance for the heat wires in your new car. To do this, we need to understand how the wires are connected and how resistance works.

Firstly, the wires are connected in a parallel wiring configuration. This means that each wire is connected side by side to the others, and the current can flow through each wire separately. In this type of configuration, the total resistance is less than the resistance of each individual wire.

To calculate the total resistance, we use the formula 1/R = 1/R1 + 1/R2 + 1/R3 +... where R is the total resistance and R1, R2, R3, etc. are the individual resistances of each wire.

In your case, you have six wires connected in parallel, each with a length of 0.8 m and a resistance of 5.0 ohm/m. To find the resistance of each individual wire, we simply multiply the length by the resistance per meter, which gives us 0.8*5 = 4 ohm.

Now, using the formula mentioned above, we can calculate the total resistance of the six wires:

1/R = 1/4 + 1/4 + 1/4 + 1/4 + 1/4 + 1/4 = 6/4 = 1.5

Therefore, the total resistance of the six wires is 1.5 ohm. However, this is still not the final answer because we need to take into account the "replacement resistance" that is mentioned in the instructionsbook.

The replacement resistance refers to the fact that when two wires are connected in parallel, the total resistance is not simply the sum of their individual resistances. Instead, the replacement resistance is equal to the product of the two resistances divided by their sum.

In your case, two wires are connected in parallel in each turn, so we need to calculate the replacement resistance for this.

For two wires with a resistance of 4 ohm each, the replacement resistance would be (4*4)/(4+4) = 2 ohm.

Now, we can use this value to calculate the total resistance for all six wires. Since there are three turns (6/2 = 3), we multiply the replacement resistance by 3, giving us a total resistance of 6 ohm.

I hope