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michonamona
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Homework Statement
Let f be a function from (1,0) to (1,0). Suppose that f is discontinuous. Show that f is not concave.
Homework Equations
The Attempt at a Solution
Let f:(0,1)-->(0,1). Suppose f is discontinous. Show that it is not concave.I've been working on this problem for over an hour. This is what I got so far.What I want to show is the following:
There exists [itex]\alpha, x_{1}, x_{2}[/itex] such that
[itex]\alpha f(x_{1})+(1-\alpha)f(x_{2}) \geq f(\alpha x_{1}+(1-\alpha)x_{2}) [/itex]
Now, let [itex]x_{1}[/itex] be a point of discontinuity of f. Thus
[itex]lim_{x \rightarrow x_{1}}f(x) \neq f(x_{1}) [/itex]
What I'm trying to show is that we can take an epsilon-neighborhood about [itex]f(x_{1})[/itex], call it [itex]N_{\epsilon}(f(x_{1}))[/itex], small enough so that for a given [itex]\alpha[/itex], such that
[itex]f(\alpha x_{1}+(1-\alpha)x_{2}) \in N_{\epsilon}(f(x_{1}))[/itex], then
[itex]\alpha f(x_{1})+(1-\alpha)f(x_{2}) \geq f(\alpha x_{1}+(1-\alpha)x_{2}) [/itex].
Is this correct? Can you provide any hints?
Thank you
A
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