- #1
mbrmbrg
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I have a homework problem as follows:
If the tangent line to y = f(x) at (4,3) passes through the point (0,2), find f(4) and f'(4).
Using the slope formula and the point-slope formula, I found that the equation of the given tangent line is y = 1/4x + 2.
Now I want to find f(x) so I can actually answer the question.
I thought I might be able to solve for f(x) using the equation
f'(a)= lim [f(x+h) - f(x)]/h
h-->0
and subsituting 1/4 for f'(a), but I can't get any farther than setting that up.
help? please?
thanks!
If the tangent line to y = f(x) at (4,3) passes through the point (0,2), find f(4) and f'(4).
Using the slope formula and the point-slope formula, I found that the equation of the given tangent line is y = 1/4x + 2.
Now I want to find f(x) so I can actually answer the question.
I thought I might be able to solve for f(x) using the equation
f'(a)= lim [f(x+h) - f(x)]/h
h-->0
and subsituting 1/4 for f'(a), but I can't get any farther than setting that up.
help? please?
thanks!
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