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RedLego
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Homework Statement
Charge of uniform density 4.50nC/m is distributed along the circle of radius R. What is the electrical potential (relative to zero at infinity) at the centre of the circle?
Answer: 254V
Homework Equations
electric potential: V=kQ/r
The Attempt at a Solution
Because the charge of uniform density is 4.50 x 10^-9 C/m
I would assumed that would equal to Q/r, and all I need to do is multiply it by k, 8.99 x 10^9Nm^2/c^2.
V= (8.99 x 10^9)(4.50 x 10^-9) = 40.455V
Of course this is incorrect, tried searching it up on google, but failed. :(